WebOct 29, 2024 · (1+x)^-3 = ( 1 + 3x+3x^2+x^3 )^-1 (1+x)^-3 = 1/(1+x)^3 Binomial theorem: (a + b)^n =(nC_0) a^nb^0+ (nC_1) a^(n-1)b^1 +(nC_2) a^(n-2)b^2 +..... (nC_n)b^n Here (a=1 ; b ... WebJul 24, 2024 · x^3-3x^2+3x-1 "note that" (x+a)^3=x^3+(a+a+a)x^2+(a.a+a.a+a.a)x+a^3 (x-1)^3toa=-1 rArr(x-1)^3=x^3+(-1-1-1)x^2+(1+1+1)x+(-1)^3 =x^3-3x^2+3x-1. ... How do …
Simplify (x-3)(x-1) Mathway
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WebApr 8, 2024 · (x-1)^4 -= x^4 -4 x^3 + 6x^2- 4x+1 We can expand the expression using the binomial theorem: (x-1)^4 -= sum_(r=0)^4 ( (n), (r) ) (x)^r(-1)^(n-r) " " = ( (4), (0) ) (x ... WebFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. WebStep 1 (Alternate Solution) Show that ( x + 1) ( x 2 − x + 1) matches the correct pattern for the formula. Since we want to factor x 3 + 1, we first identify a and b. Since a is the cube root of the first term, we know a = x 3 3 = x . Likewise, since b is the cube root of the second term, we know b = 1 3 = 1 . Step 2. Write down the factored ... nahpc annual forum 2021