WebApr 19, 2024 · SELECT * FROM department; Note: Here * represents all. If we execute this query, the entire table will be displayed. Output : The query for the data: Use the below syntax for querying for all students with greater marks than the average of the class: Syntax: SELECT column1 FROM table_name WHERE column2 > (SELECT AVG ( column2) FROM … WebAug 3, 2024 · SQL SELECT statement can be used along with COUNT (*) function to count and display the data values. The COUNT (*) function represents the count of all rows …
SQL_Zoo/8_solutions.sql at master · Chenzilla/SQL_Zoo · …
WebSELECT Department, COUNT ( *) FROM Employees GROUP BY Department; -- 2.10 Select all the data of employees, including each employee's department's data. select a. *, b. * from employees a join departments b on a. department = b. code; SELECT SSN, E. Name AS Name_E, LastName, D. Name AS Name_D, Department, Code, Budget WebCreate function dept count (dept_name varchar (20)) begin. declare d count integer; select count (*) into d count. from instructor. where instructor.dept_name= dept_name. return d … tod und spiele ard
SQL query for distinct professors and courses - Stack Overflow
Web1. List the teachers who have NULL for their department. Why we cannot use = Submit SQL Restore default result 2. Note the INNER JOIN misses the teachers with no department and the departments with no teacher. Submit SQL Restore default result 3. Use a different JOIN so that all teachers are listed. Submit SQL Restore default result 4. Webset dept value of all teachers to 0. set dept value of all teachers without department to 0. Query: SELECT name, CASE WHEN phone = 2752 THEN 'two' WHEN phone = 2753 THEN 'three' WHEN phone = 2754 THEN 'four' END AS digit FROM teacher. shows following 'digit': 'four' for Throd. NULL for all teachers. NULL for Shrivell. WebSELECT COUNT(name), COUNT(mobile) FROM teacher 8. Use COUNT and GROUP BY dept.name to show each department and the number of staff. Use a RIGHT JOIN to ensure that the Engineering department is listed. SELECT dept.name, COUNT(teacher.name) FROM teacher RIGHT JOIN dept ON (teacher.dept=dept.id) GROUP BY dept.name; 9. Use CASE … tod unter lametta 2 download